Noche de Estrellas

Wednesday, September 19, 2012

Calculations

$a = \frac{2 \pi v}{T}$

$v = \frac{2 \pi r}{T}$

$a = \frac{4 \pi ^2 r}{T^2}$

$F = m a$

$\frac{G M m}{r^2} = \frac{m 4 \pi ^2 r}{T^2}$

$r^3 = \frac{G M T^2}{4 \pi^2}$

$r$ in $m$ and T in $s$

$T = 365\times 24 \times 60 \times60$

$G = 6.7 \times 10^{-11} \frac{m^3}{kg}$

$M = 2 \times 10^{30} kg$

$r = 1.5 \times 10^{11} m$

Astronomical Unit

Eduardo Cantoral at 4:34 PM

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Wednesday, September 19, 2012

Calculations

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